The charging capacitor
Home >
All Problems > The charging capacitor
The voltage across a charging capacitor in an RC circuit is given by V=Vo*(1-e^(-t/(R*C))). Vo is the applied DC voltage, R is the resistance and C the capacitance. The product RC is called the time constant.
Plot the graph of y(t)=1-e^(-0.5*t) for 0<=t<9 with a sampling interval of 0.01. Here y represents the voltage across the capacitor with Vo=1 and RC=0.5
a) Use your graph to estimate after how long the voltage has reached half of its maximum value.
b) Calculate the above value by solving the equation 0.5=1-e^(-0.5*t)
c) Find a relationship between any value of the time constant and the corresponding time taken to reach half the maximum voltage.
#maxima #differentiation #chargingcapacitor #timeconstant #engineeringmaths
plotXpose app is available on Google Play and App Store
Google Play and the Google Play logo are trademarks of Google LLC.
A version will shortly be available for Windows.
A version will shortly be available for Windows.
plotXpose app is a companion to the book Mathematics for Electrical Engineering and Computing by Mary Attenborough, published by Newnes, 2003.