Is this a fix?
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To find a fix-point function suitable for finding a square root, for instance of 2, we can begin with
t^2= 2
subtract the square of an integer from both sides (in this case 1) gives:
t^2-1=1
use the difference of two squares factorization on the left-hand-side to get
(t-1)(t+1)=1
divide by one of the factors on the left-hand-side giving (t-1)=1/(t+1)
and finally add 1 to both sides giving
t=1+1/(t+1)
i.e. the fix point function to use is fix(t)=1+1/(t+1).
Plot the graph of y(t)=t^2-2 and perform zero finding using fix(t). The value of t found should be the square root of 2.
Use the same method to find the square root of 5.
Can a similar method of rearrangement work for cube roots?
#sequences #equationsolving #numericalmethods
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Versions will shortly be available for iOS and Windows.
plotXpose app is a companion to the book Mathematics for Electrical Engineering and Computing by Mary Attenborough, published by Newnes, 2003.